Optimal. Leaf size=138 \[ -\frac{2 \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{15 a^3}-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2+\frac{x}{30 a^2}+\frac{2 \tanh ^{-1}(a x)^2}{15 a^3}-\frac{\tanh ^{-1}(a x)}{30 a^3}-\frac{4 \log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)}{15 a^3}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2+\frac{2 x^2 \tanh ^{-1}(a x)}{15 a}-\frac{x^3}{30} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.413488, antiderivative size = 138, normalized size of antiderivative = 1., number of steps used = 24, number of rules used = 10, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {6014, 5916, 5980, 321, 206, 5984, 5918, 2402, 2315, 302} \[ -\frac{2 \text{PolyLog}\left (2,1-\frac{2}{1-a x}\right )}{15 a^3}-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2+\frac{x}{30 a^2}+\frac{2 \tanh ^{-1}(a x)^2}{15 a^3}-\frac{\tanh ^{-1}(a x)}{30 a^3}-\frac{4 \log \left (\frac{2}{1-a x}\right ) \tanh ^{-1}(a x)}{15 a^3}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2+\frac{2 x^2 \tanh ^{-1}(a x)}{15 a}-\frac{x^3}{30} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 6014
Rule 5916
Rule 5980
Rule 321
Rule 206
Rule 5984
Rule 5918
Rule 2402
Rule 2315
Rule 302
Rubi steps
\begin{align*} \int x^2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2 \, dx &=-\left (a^2 \int x^4 \tanh ^{-1}(a x)^2 \, dx\right )+\int x^2 \tanh ^{-1}(a x)^2 \, dx\\ &=\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2-\frac{1}{3} (2 a) \int \frac{x^3 \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx+\frac{1}{5} \left (2 a^3\right ) \int \frac{x^5 \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx\\ &=\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2+\frac{2 \int x \tanh ^{-1}(a x) \, dx}{3 a}-\frac{2 \int \frac{x \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx}{3 a}-\frac{1}{5} (2 a) \int x^3 \tanh ^{-1}(a x) \, dx+\frac{1}{5} (2 a) \int \frac{x^3 \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx\\ &=\frac{x^2 \tanh ^{-1}(a x)}{3 a}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{\tanh ^{-1}(a x)^2}{3 a^3}+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2-\frac{1}{3} \int \frac{x^2}{1-a^2 x^2} \, dx-\frac{2 \int \frac{\tanh ^{-1}(a x)}{1-a x} \, dx}{3 a^2}-\frac{2 \int x \tanh ^{-1}(a x) \, dx}{5 a}+\frac{2 \int \frac{x \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx}{5 a}+\frac{1}{10} a^2 \int \frac{x^4}{1-a^2 x^2} \, dx\\ &=\frac{x}{3 a^2}+\frac{2 x^2 \tanh ^{-1}(a x)}{15 a}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{2 \tanh ^{-1}(a x)^2}{15 a^3}+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2-\frac{2 \tanh ^{-1}(a x) \log \left (\frac{2}{1-a x}\right )}{3 a^3}+\frac{1}{5} \int \frac{x^2}{1-a^2 x^2} \, dx-\frac{\int \frac{1}{1-a^2 x^2} \, dx}{3 a^2}+\frac{2 \int \frac{\tanh ^{-1}(a x)}{1-a x} \, dx}{5 a^2}+\frac{2 \int \frac{\log \left (\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{3 a^2}+\frac{1}{10} a^2 \int \left (-\frac{1}{a^4}-\frac{x^2}{a^2}+\frac{1}{a^4 \left (1-a^2 x^2\right )}\right ) \, dx\\ &=\frac{x}{30 a^2}-\frac{x^3}{30}-\frac{\tanh ^{-1}(a x)}{3 a^3}+\frac{2 x^2 \tanh ^{-1}(a x)}{15 a}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{2 \tanh ^{-1}(a x)^2}{15 a^3}+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2-\frac{4 \tanh ^{-1}(a x) \log \left (\frac{2}{1-a x}\right )}{15 a^3}-\frac{2 \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-a x}\right )}{3 a^3}+\frac{\int \frac{1}{1-a^2 x^2} \, dx}{10 a^2}+\frac{\int \frac{1}{1-a^2 x^2} \, dx}{5 a^2}-\frac{2 \int \frac{\log \left (\frac{2}{1-a x}\right )}{1-a^2 x^2} \, dx}{5 a^2}\\ &=\frac{x}{30 a^2}-\frac{x^3}{30}-\frac{\tanh ^{-1}(a x)}{30 a^3}+\frac{2 x^2 \tanh ^{-1}(a x)}{15 a}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{2 \tanh ^{-1}(a x)^2}{15 a^3}+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2-\frac{4 \tanh ^{-1}(a x) \log \left (\frac{2}{1-a x}\right )}{15 a^3}-\frac{\text{Li}_2\left (1-\frac{2}{1-a x}\right )}{3 a^3}+\frac{2 \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-a x}\right )}{5 a^3}\\ &=\frac{x}{30 a^2}-\frac{x^3}{30}-\frac{\tanh ^{-1}(a x)}{30 a^3}+\frac{2 x^2 \tanh ^{-1}(a x)}{15 a}-\frac{1}{10} a x^4 \tanh ^{-1}(a x)+\frac{2 \tanh ^{-1}(a x)^2}{15 a^3}+\frac{1}{3} x^3 \tanh ^{-1}(a x)^2-\frac{1}{5} a^2 x^5 \tanh ^{-1}(a x)^2-\frac{4 \tanh ^{-1}(a x) \log \left (\frac{2}{1-a x}\right )}{15 a^3}-\frac{2 \text{Li}_2\left (1-\frac{2}{1-a x}\right )}{15 a^3}\\ \end{align*}
Mathematica [A] time = 0.241826, size = 95, normalized size = 0.69 \[ -\frac{-4 \text{PolyLog}\left (2,-e^{-2 \tanh ^{-1}(a x)}\right )+a^3 x^3+2 \left (3 a^5 x^5-5 a^3 x^3+2\right ) \tanh ^{-1}(a x)^2+\tanh ^{-1}(a x) \left (3 a^4 x^4-4 a^2 x^2+8 \log \left (e^{-2 \tanh ^{-1}(a x)}+1\right )+1\right )-a x}{30 a^3} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.048, size = 205, normalized size = 1.5 \begin{align*} -{\frac{{a}^{2}{x}^{5} \left ({\it Artanh} \left ( ax \right ) \right ) ^{2}}{5}}+{\frac{{x}^{3} \left ({\it Artanh} \left ( ax \right ) \right ) ^{2}}{3}}-{\frac{a{x}^{4}{\it Artanh} \left ( ax \right ) }{10}}+{\frac{2\,{x}^{2}{\it Artanh} \left ( ax \right ) }{15\,a}}+{\frac{2\,{\it Artanh} \left ( ax \right ) \ln \left ( ax-1 \right ) }{15\,{a}^{3}}}+{\frac{2\,{\it Artanh} \left ( ax \right ) \ln \left ( ax+1 \right ) }{15\,{a}^{3}}}+{\frac{ \left ( \ln \left ( ax-1 \right ) \right ) ^{2}}{30\,{a}^{3}}}-{\frac{2}{15\,{a}^{3}}{\it dilog} \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }-{\frac{\ln \left ( ax-1 \right ) }{15\,{a}^{3}}\ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }-{\frac{1}{15\,{a}^{3}}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }+{\frac{\ln \left ( ax+1 \right ) }{15\,{a}^{3}}\ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) }-{\frac{ \left ( \ln \left ( ax+1 \right ) \right ) ^{2}}{30\,{a}^{3}}}-{\frac{{x}^{3}}{30}}+{\frac{x}{30\,{a}^{2}}}+{\frac{\ln \left ( ax-1 \right ) }{60\,{a}^{3}}}-{\frac{\ln \left ( ax+1 \right ) }{60\,{a}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [A] time = 1.01269, size = 234, normalized size = 1.7 \begin{align*} -\frac{1}{60} \, a^{2}{\left (\frac{2 \, a^{3} x^{3} - 2 \, a x + 2 \, \log \left (a x + 1\right )^{2} - 4 \, \log \left (a x + 1\right ) \log \left (a x - 1\right ) - 2 \, \log \left (a x - 1\right )^{2} - \log \left (a x - 1\right )}{a^{5}} + \frac{8 \,{\left (\log \left (a x - 1\right ) \log \left (\frac{1}{2} \, a x + \frac{1}{2}\right ) +{\rm Li}_2\left (-\frac{1}{2} \, a x + \frac{1}{2}\right )\right )}}{a^{5}} + \frac{\log \left (a x + 1\right )}{a^{5}}\right )} - \frac{1}{30} \, a{\left (\frac{3 \, a^{2} x^{4} - 4 \, x^{2}}{a^{2}} - \frac{4 \, \log \left (a x + 1\right )}{a^{4}} - \frac{4 \, \log \left (a x - 1\right )}{a^{4}}\right )} \operatorname{artanh}\left (a x\right ) - \frac{1}{15} \,{\left (3 \, a^{2} x^{5} - 5 \, x^{3}\right )} \operatorname{artanh}\left (a x\right )^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (a^{2} x^{4} - x^{2}\right )} \operatorname{artanh}\left (a x\right )^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \int - x^{2} \operatorname{atanh}^{2}{\left (a x \right )}\, dx - \int a^{2} x^{4} \operatorname{atanh}^{2}{\left (a x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -{\left (a^{2} x^{2} - 1\right )} x^{2} \operatorname{artanh}\left (a x\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]